4x-[3(x+1)-(x+4)]=1

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Solution for 4x-[3(x+1)-(x+4)]=1 equation:


Simplifying
4x + -1[3(x + 1) + -1(x + 4)] = 1

Reorder the terms:
4x + -1[3(1 + x) + -1(x + 4)] = 1
4x + -1[(1 * 3 + x * 3) + -1(x + 4)] = 1
4x + -1[(3 + 3x) + -1(x + 4)] = 1

Reorder the terms:
4x + -1[3 + 3x + -1(4 + x)] = 1
4x + -1[3 + 3x + (4 * -1 + x * -1)] = 1
4x + -1[3 + 3x + (-4 + -1x)] = 1

Reorder the terms:
4x + -1[3 + -4 + 3x + -1x] = 1

Combine like terms: 3 + -4 = -1
4x + -1[-1 + 3x + -1x] = 1

Combine like terms: 3x + -1x = 2x
4x + -1[-1 + 2x] = 1
4x + [-1 * -1 + 2x * -1] = 1
4x + [1 + -2x] = 1

Reorder the terms:
1 + 4x + -2x = 1

Combine like terms: 4x + -2x = 2x
1 + 2x = 1

Add '-1' to each side of the equation.
1 + -1 + 2x = 1 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = 1 + -1
2x = 1 + -1

Combine like terms: 1 + -1 = 0
2x = 0

Solving
2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '2'.
x = 0

Simplifying
x = 0

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